3x^2-3(x^2+4x+4)=0

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Solution for 3x^2-3(x^2+4x+4)=0 equation:


Simplifying
3x2 + -3(x2 + 4x + 4) = 0

Reorder the terms:
3x2 + -3(4 + 4x + x2) = 0
3x2 + (4 * -3 + 4x * -3 + x2 * -3) = 0
3x2 + (-12 + -12x + -3x2) = 0

Reorder the terms:
-12 + -12x + 3x2 + -3x2 = 0

Combine like terms: 3x2 + -3x2 = 0
-12 + -12x + 0 = 0
-12 + -12x = 0

Solving
-12 + -12x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -12x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -12x = 0 + 12
-12x = 0 + 12

Combine like terms: 0 + 12 = 12
-12x = 12

Divide each side by '-12'.
x = -1

Simplifying
x = -1

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